Discussion:
WSJT-X: WSPR DT error?
(too old to reply)
Bill Somerville
2015-06-06 00:31:43 UTC
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Hi All,

I note that there appears to be a time offset somewhere in the WSPR
round trip, I see decodes always with a -1.0 DT when both ends are
running with the same wall clock time.

73
Bill
G4WJS.

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Steven Franke
2015-06-06 00:34:20 UTC
Permalink
Post by Bill Somerville
I note that there appears to be a time offset somewhere in the WSPR
round trip, I see decodes always with a -1.0 DT when both ends are
running with the same wall clock time.
I encountered this when I was writing the decoder. Most programs start TX at 1 second in, whereas the decoders define t0 to be 2 seconds in.
Steve k9an


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Joe Taylor
2015-06-06 00:37:07 UTC
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Yes. Probably we should add 1 s to the DT reported by wsprd.

-- Joe
Post by Steven Franke
Post by Bill Somerville
I note that there appears to be a time offset somewhere in the WSPR
round trip, I see decodes always with a -1.0 DT when both ends are
running with the same wall clock time.
I encountered this when I was writing the decoder. Most programs start TX at 1 second in, whereas the decoders define t0 to be 2 seconds in.
Steve k9an
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Steven Franke
2015-06-06 00:51:53 UTC
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Joe, Bill,
The reason that I haven’t changed it till now is because of the potential confusion that it might cause when users compare the results from tried-and-true old decoders with the new decoder. If that’s not a concern, then I’m happy to make the change.
Steve k9an
Post by Joe Taylor
Yes. Probably we should add 1 s to the DT reported by wsprd.
-- Joe
Post by Steven Franke
Post by Bill Somerville
I note that there appears to be a time offset somewhere in the WSPR
round trip, I see decodes always with a -1.0 DT when both ends are
running with the same wall clock time.
I encountered this when I was writing the decoder. Most programs start TX at 1 second in, whereas the decoders define t0 to be 2 seconds in.
Steve k9an
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